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Saturday, 31 October

JEE Main 2020 · ChemistryMultiple choiceSingle correctHardMulti-step

JEE Main 4 September 2020, Shift 2, Chemistry Q34

Question 34 of 75 in this shift, Chemistry question 9 of 25.

The reaction in which the hybridisation of the underlined atom is affected is :
  1. (1)Xe‾F4+SbF5→\underline{\mathrm{Xe}}\mathrm{F_4 + SbF_5 \rightarrow}Official answer
  2. (2)H2S‾O4+NaCl→420 K\mathrm{H_2}\underline{\mathrm{S}}\mathrm{O_4 + NaCl \xrightarrow{420\ K}}
  3. (3)N‾H3→H+\underline{\mathrm{N}}\mathrm{H_3 \xrightarrow{H^+}}
  4. (4)H3P‾O2→Disproportionation\mathrm{H_3}\underline{\mathrm{P}}\mathrm{O_2 \xrightarrow{Disproportionation}}

Official answer

Option 1

NTA final key (Sep 2020).

Chapter
Chemical Bonding and Molecular Structure
Topic
Group 17 & 18
Idea tested
Xenon Fluorides as Fluoride Donors

Same idea in other shifts

Asked 2× in all
  1. 8 Apr 2023, Shift 1 · Q88XeF4\mathrm{XeF_4} reacts with SbF5\mathrm{SbF_5} to form [XeFm]n+[SbFy]z−\mathrm{[XeF_m]^{n+}[SbF_y]^{z-}}. m+n+y+z\mathrm{m + n + y + z} = ________MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.