Learn

Saturday, 31 October

JEE Main 2020 · PhysicsNumerical answerNumerical valueEasyData or graph

JEE Main 4 September 2020, Shift 2, Physics Q21

Question 21 of 75 in this shift, Physics question 21 of 25.

The speed verses time graph for a particle is shown in the figure. The distance travelled (in m) by the particle during the time interval t=0t=0 to t=5t=5 s will be __________.

The figure, in words

Graph with vertical axis labelled u (ms^-1) with ticks 2, 4, 6, 8, 10 and horizontal axis labelled time (s) with ticks 1, 2, 3, 4, 5. A straight line rises from the origin to a dot at t = 5, u = 8 and continues slightly beyond.

Official answer

20.00

NTA final key (Sep 2020).

Chapter
Motion in a Straight Line
Topic
Kinematics in 1D
Idea tested
Kinematic Graph Areas

Same idea in other shifts

Asked 3× in all
  1. 5 Apr 2026, Shift 2 · Q29The velocity (vv) versus time (tt) plot of a particle is shown in the figure, for a time interval of 40 s. The total distance travelled…EasyDiagram basedHas a figure
  2. 8 Apr 2023, Shift 2 · Q38Given below are two statements: Statement I : Area under velocity- time graph gives the distance travelled by the body in a given time.…EasyTwo statements

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.