JEE Main 2020 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 4 September 2020, Shift 1, Physics Q25

Question 25 of 75 in this shift, Physics question 25 of 25.

In the line spectra of hydrogen atom, difference between the largest and the shortest wavelengths of the Lyman series is 304 Å. The corresponding difference for the Paschan series in Å is : __________.

Official answer

10553.00 to 10554.00

NTA final key (Sep 2020). Any value in the range scored.

Chapter: Atoms
Topic: Bohr's Atomic Model
Idea tested: Shortest and Longest Wavelengths

Same idea in other shifts

Asked 8× in all

7 Apr 2025, Shift 1 · Q43For a hydrogen atom, the ratio of the largest wavelength of Lyman series to that of the Balmer series isEasySingle correct
5 Apr 2024, Shift 2 · Q60The shortest wavelength of the spectral lines in the Lyman series of hydrogen spectrum is 915 $\mathrm{\AA}$ . The longest wavelength of…MediumNumerical value
6 Apr 2024, Shift 1 · Q48The ratio of the shortest wavelength of Balmer series to the shortest wavelength of Lyman series for hydrogen atom is :EasySingle correct
6 Apr 2024, Shift 2 · Q48The longest wavelength associated with Paschen series is : (Given $R_H=1.097\times10^7$ SI unit)EasySingle correct
10 Apr 2023, Shift 2 · Q56If 917 $\mathrm{\AA}$ be the lowest wavelength of Lyman series then the lowest wavelength of Balmer series will be ____________…EasyNumerical value
3 Aug 2021, Shift 2 · Q23The ratio of shortest wavelength to the largest wavelength in Brackett series of atomic spectra for hydrogen atom is $x : 25$ , where the…MediumNumerical value
24 Feb 2021, Shift 1 · Q17In the given figure, the energy levels of hydrogen atom have been shown along with some transitions marked A, B, C, D and E. The…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.