JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyCalculation
JEE Main 4 September 2020, Shift 1, Physics Q12
Question 12 of 75 in this shift, Physics question 12 of 25.
A battery of 3.0 V is connected to a resistor dissipating 0.5 W of power. If the terminal voltage of the battery is 2.5 V, the power dissipated within the internal resistance is :
- (1)0.125 W
- (2)0.50 W
- (3)0.072 W
- (4)0.10 WOfficial answer
Official answer
Option 4
NTA final key (Sep 2020).
- Chapter
- Current Electricity
- Topic
- Kirchhoff's Laws
- Idea tested
- Cell EMF and Internal Resistance