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Saturday, 31 October

JEE Main 2020 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 3 September 2020, Shift 2, Maths Q60

Question 60 of 75 in this shift, Maths question 10 of 25.

If ∫sin⁡−1(x1+x)dx=A(x)tan⁡−1(x)+B(x)+C\int \sin^{-1}\left(\sqrt{\frac{x}{1+x}}\right) dx = A(x)\tan^{-1}(\sqrt{x}) + B(x) + C, where C is a constant of integration, then the ordered pair (A(x),B(x))(A(x), B(x)) can be :
  1. (1)(x+1,−x)(x + 1, -\sqrt{x})Official answer
  2. (2)(x+1,x)(x + 1, \sqrt{x})
  3. (3)(x−1,−x)(x - 1, -\sqrt{x})
  4. (4)(x−1,x)(x - 1, \sqrt{x})

Official answer

Option 1

NTA final key (Sep 2020).

Chapter
Integrals

Same idea in other shifts

Asked 2× in all
  1. 4 Aug 2021, Shift 2 · Q69If ∫sin⁡−1(2x+24x2+8x+13)dx=Atan⁡−1(2x+23)+Blog⁡e(4x2+8x+13)+C\int\sin^{-1}\left(\frac{2x+2}{\sqrt{4x^2+8x+13}}\right)dx=A\tan^{-1}\left(\frac{2x+2}{3}\right)+B\log_e\left(4x^2+8x+13\right)+C (C…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.