JEE Main 2020 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 3 September 2020, Shift 2, Chemistry Q49

Question 49 of 75 in this shift, Chemistry question 24 of 25.

The volume (in mL) of 0.1 N

\mathrm{NaOH}

required to neutralise 10 mL of 0.1 N phosphinic acid is __________.

Official answer

10.00

NTA final key (Sep 2020).

Chapter: Some Basic Concepts of Chemistry
Topic: Mole Concept
Idea tested: Normality and n-factor Calculation

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.