JEE Main 2020 · ChemistryMultiple choiceDiagram basedHardApplication

JEE Main 3 September 2020, Shift 2, Chemistry Q40

Question 40 of 75 in this shift, Chemistry question 15 of 25.

Consider the following reaction : [figure]

\xrightarrow[\text{anhydride}]{\text{Chromic}}

‘P’ The product ‘P’ gives positive ceric ammonium nitrate test. This is because of the presence of which of these

-

OH group(s) ?

The figure, in words

Drawn polycyclic skeleton of three fused six-membered rings. Left ring is a benzene-type ring (alternating double bonds drawn) bearing O with a circled H labelled d at its left (written 'd (H) O'). The middle ring has an O with a circled H labelled c on its top carbon. The right ring has a carbon bearing CH3 and an O with a circled H labelled b, and another ring carbon carries a side chain with a C=C double bond followed by CH2 and an O with a circled H labelled a. The arrow below is labelled 'Chromic anhydride' and leads to 'P'.

(1)(c) and (d)
(2)(b) and (d)
(3)(b) onlyOfficial answer
(4)(d) only

Official answer

Option 3

NTA final key (Sep 2020).

Chapter: Alcohols, Phenols and Ethers
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy