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Saturday, 31 October

JEE Main 2020 · ChemistryMultiple choiceSingle correctMediumMulti-step

JEE Main 3 September 2020, Shift 1, Chemistry Q28

Question 28 of 75 in this shift, Chemistry question 3 of 25.

Henry’s constant (in kbar) for four gases α\alpha, β\beta, γ\gamma and δ\delta in water at 298 K is given below :
α\alphaβ\betaγ\gammaδ\delta
KH\mathrm{K_H}5022×10−52\times10^{-5}0.5
(density of water =103=10^3 kg m−3\mathrm{kg\ m^{-3}} at 298 K) This table implies that :

The figure, in words

A small table in the stem: header row alpha, beta, gamma, delta; row K_H with values 50, 2, 2x10^-5, 0.5.
  1. (1)α\alpha has the highest solubility in water at a given pressure
  2. (2)solubility of γ\gamma at 308 K is lower than at 298 KOfficial answer
  3. (3)The pressure of a 55.5 molal solution of γ\gamma is 1 bar
  4. (4)The pressure of a 55.5 molal solution of δ\delta is 250 barOfficial answer

Official answer

Options 2 and 4

NTA final key (Sep 2020): multiple options accepted. Either option scored full marks.

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.