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Saturday, 31 October

JEE Main 2020 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 3 September 2020, Shift 1, Physics Q23

Question 23 of 75 in this shift, Physics question 23 of 25.

A bakelite beaker has volume capacity of 500 cc at 30°C. When it is partially filled with Vm_m volume (at 30°C) of mercury, it is found that the unfilled volume of the beaker remains constant as temperature is varied. If γ(beaker)\gamma_{(\mathrm{beaker})} = 6×\times10−6^{-6} °C−1^{-1} and γ(mercury)\gamma_{(\mathrm{mercury})} = 1.5×\times10−4^{-4} °C−1^{-1}, where γ\gamma is the coefficient of volume expansion, then Vm_m (in cc) is close to __________.

Official answer

20.00

NTA final key (Sep 2020).