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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 3 September 2020, Shift 1, Physics Q17

Question 17 of 75 in this shift, Physics question 17 of 25.

In a Young's double slit experiment, light of 500 nm is used to produce an interference pattern. When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :
  1. (1)0.57°Official answer
  2. (2)1.7°
  3. (3)0.07°
  4. (4)0.17°

Official answer

Option 1

NTA final key (Sep 2020).

Same idea in other shifts

Asked 2× in all
  1. 28 Jun 2022, Shift 2 · Q53In a Young’s double slit experiment, an angular width of the fringe is 0.35° on a screen placed at 2 m away for particular wavelength of…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.