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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 2 September 2020, Shift 2, Physics Q14

Question 14 of 75 in this shift, Physics question 14 of 25.

An inductance coil has a reactance of 100 Ω\Omega. When an AC signal of frequency 1000 Hz is applied to the coil, the applied voltage leads the current by 45°. The self-inductance of the coil is :
  1. (1)1.1×10−11.1\times10^{-1} H
  2. (2)1.1×10−21.1\times10^{-2} HOfficial answer
  3. (3)5.5×10−55.5\times10^{-5} H
  4. (4)6.7×10−76.7\times10^{-7} H

Official answer

Option 2

NTA final key (Sep 2020).