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JEE Main 2020 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 9 January 2020, Shift 2, Maths Q61

Question 61 of 75 in this shift, Maths question 11 of 25, Section A.

Let a function

f:[0,5]\to\mathbf{R}

be continuous,

f(1)=3

and

F

be defined as :

F(x)=\int_1^x t^2g(t)\,dt

, where

g(t)=\int_1^t f(u)\,du

. Then for the function

F

, the point

x=1

is :

(1)not a critical point.
(2)a point of local maxima.
(3)a point of local minima.Official answer
(4)a point of inflection.

Official answer

Option 3

NTA final key (Jan 2020).

Chapter: Application of Derivatives
Topic: Maxima and Minima
Idea tested: Extrema of Integral Functions

Same idea in other shifts

Asked 2× in all

27 Jun 2022, Shift 2 · Q7If $m$ and $n$ respectively are the number of local maximum and local minimum points of the function…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.