If $A=\{x\in\mathbf{R}:|x|<2\}$ and $B=\{x\in\mathbf{R}:|x-2|\ge 3\}$; then :

Option 2: $B-A=\mathbf{R}-(-2,5)$

JEE Main 2020 · MathsMultiple choiceSingle correctEasyApplication

JEE Main 9 January 2020, Shift 2, Maths Q51

Question 51 of 75 in this shift, Maths question 1 of 25, Section A.

A=\{x\in\mathbf{R}:|x|<2\}

and

B=\{x\in\mathbf{R}:|x-2|\ge 3\}

; then :

(1) $A-B=[-1,2)$
(2) $B-A=\mathbf{R}-(-2,5)$ Official answer
(3) $A\cap B=(-2,-1)$
(4) $A\cup B=\mathbf{R}-(2,5)$

Official answer

Option 2

NTA final key (Jan 2020).

Chapter: Relations and Functions
Topic: Sets and Relations
Idea tested: Intervals as Subsets of R

Same idea in other shifts

Asked 3× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.