JEE Main 2020 · ChemistryMultiple choiceDiagram basedMediumConceptual

JEE Main 9 January 2020, Shift 1, Chemistry Q40

Question 40 of 75 in this shift, Chemistry question 15 of 25, Section A.

The increasing order of basicity for the following intermediates is (from weak to strong)

The figure, in words

Five drawn species labelled (i) to (v), each with a circled minus sign: (i) a carbon with a circled minus at its right, bonded to H3C on the left, CH3 above and CH3 below; (ii)

\mathrm{H_2C{=}CH-CH_2}

with a circled minus above the last CH2; (iii)

\mathrm{HC{\equiv}C}

with a circled minus above the last C; (iv)

\mathrm{CH_3}

with a circled minus above it; (v) CN with a circled minus above it.

(1)(v) < (i) < (iv) < (ii) < (iii)
(2)(v) < (iii) < (ii) < (iv) < (i)Official answer
(3)(iii) < (i) < (ii) < (iv) < (v)
(4)(iii) < (iv) < (ii) < (i) < (v)

Official answer

Option 2

NTA final key (Jan 2020).

Chapter: Organic Chemistry: Some Basic Principles and Techniques
Topic: Inductive and Electromeric Effects
Idea tested: Carbanion Stability

JEE Main 9 January 2020, Shift 1, Chemistry Q40

Same idea in other shifts