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Saturday, 31 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 9 January 2020, Shift 1, Physics Q2

Question 2 of 75 in this shift, Physics question 2 of 25, Section A.

Consider a force F⃗=−xi^+yj^\vec{F} = -x\hat{i} + y\hat{j}. The work done by this force in moving a particle from point A(1, 0) to B(0, 1) along the line segment is : (all quantities are in SI units)

The figure, in words

Axes X and Y with origin labelled (0, 0); point A (1, 0) on the X axis and point B (0, 1) on the Y axis; a straight line segment joins A to B with an arrow pointing from A towards B; the vertical line from (0, 0) to B and the horizontal line from (0, 0) to A are also drawn.
  1. (1)12\frac{1}{2}
  2. (2)32\frac{3}{2}
  3. (3)11Official answer
  4. (4)22

Official answer

Option 3

NTA final key (Jan 2020).

Chapter
Work, Energy and Power
Topic
Work and Kinetic Energy
Idea tested
Work via Line Integrals

Same idea in other shifts

Asked 2× in all
  1. 24 Jun 2022, Shift 1 · Q39A particle experiences a variable force F⃗=(4xi^+3y2j^)\vec{F}=(4x\hat{i}+3y^2\hat{j}) in a horizontal xx-yy plane. Assume distance in meters and…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.