JEE Main 2020 (9 Jan, Shift 1) Physics Q14: Lorentz Force

Question

The electric fields of two plane electromagnetic plane waves in vacuum are given by
$\overrightarrow{E_1} = E_0\hat{j}\ \cos(\omega t - kx)$ and
$\overrightarrow{E_2} = E_0\hat{k}\ \cos(\omega t - ky)$
At t=0, a particle of charge q is at origin with a velocity $\overrightarrow{v} = 0.8\,c\hat{j}$ (c is the speed of light in vaccum). The instantaneous force experienced by the particle is :

Accepted Answer

Option 2: $E_0 q\left(0.8\hat{i} + \hat{j} + 0.2\hat{k}\right)$

Answer

$E_0 q\left(-0.8\hat{i} + \hat{j} + \hat{k}\right)$

Answer

$E_0 q\left(0.8\hat{i} + \hat{j} + 0.2\hat{k}\right)$

Answer

$E_0 q\left(0.4\hat{i} - 3\hat{j} + 0.8\hat{k}\right)$

Answer

$E_0 q\left(0.8\hat{i} - \hat{j} + 0.4\hat{k}\right)$

JEE Main 9 January 2020, Shift 1, Physics Q14

Same idea in other shifts