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Saturday, 31 October

JEE Main 2020 · MathsMultiple choiceSingle correctEasyCalculation

JEE Main 8 January 2020, Shift 2, Maths Q54

Question 54 of 75 in this shift, Maths question 4 of 25, Section A.

If A=(2294)A = \begin{pmatrix} 2 & 2 \\ 9 & 4 \end{pmatrix} and I=(1001)I = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}, then 10A−110A^{-1} is equal to :
  1. (1)6I−A6I - A
  2. (2)4I−A4I - A
  3. (3)A−4IA - 4I
  4. (4)A−6IA - 6IOfficial answer

Official answer

Option 4

NTA final key (Jan 2020).

Chapter
Matrices

Same idea in other shifts

Asked 2× in all
  1. 8 Apr 2023, Shift 2 · Q4If A=[15λ10]A = \begin{bmatrix} 1 & 5 \\ \lambda & 10 \end{bmatrix}, A−1=αA+βIA^{-1} = \alpha A + \beta I and α+β=−2\alpha + \beta = -2, then…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.