JEE Main 2017 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2017 (offline), Maths Q80

Question 80 of 90 in this shift, Maths question 20 of 30.

The eccentricity of an ellipse whose centre is at the origin is

\frac{1}{2}

. If one of its directrices is

x=-4

, then the equation of the normal to it at

\left(1,\frac{3}{2}\right)

is :

(1) $4x-2y=1$ Official answer
(2) $4x+2y=7$
(3) $x+2y=4$
(4) $2y-x=2$

Official answer

Option 1

CBSE answer key (25/04/2017, used for result).

Chapter: Conic Sections
Topic: Normals to Conics
Idea tested: Ellipse Normal Point Form

Same idea in other shifts

Asked 3× in all

8 Jan 2020, Shift 1 · Q64Let the line $y=mx$ and the ellipse $2x^2+y^2=1$ intersect at a point P in the first quadrant. If the normal to this ellipse at P meets…MediumSingle correct
4 Sep 2020, Shift 2 · Q66Let $x=4$ be a directrix to an ellipse whose centre is at the origin and its eccentricity is $\frac{1}{2}$ . If P(1, $\beta$ ), $\beta > 0$ …MediumSingle correct

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.