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JEE Main 2017 · PhysicsMultiple choiceSingle correctHardMulti-step

JEE Main 2 April 2017 (offline), Physics Q5

Question 5 of 90 in this shift, Physics question 5 of 30.

The moment of inertia of a uniform cylinder of length

l

and radius

R

about its perpendicular bisector is I. What is the ratio

l/R

such that the moment of inertia is minimum ?

(1) $\sqrt{\frac{3}{2}}$ Official answer
(2) $\frac{\sqrt{3}}{2}$
(3) $1$
(4) $\frac{3}{\sqrt{2}}$

Official answer

Option 1

CBSE answer key (25/04/2017, used for result).

Chapter: System of Particles and Rotational Motion
Topic: Moment of Inertia
Idea tested: MOI of a Cylinder About Transverse Axis

Same idea in other shifts

Asked 2× in all

3 Sep 2020, Shift 1 · Q4Moment of inertia of a cylinder of mass M, length L and radius R about an axis passing through its centre and perpendicular to the axis of…HardSingle correct

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.