JEE Main 2017 · ChemistryMultiple choiceSingle correctEasyCalculation

JEE Main 2 April 2017 (offline), Chemistry Q32

Question 32 of 90 in this shift, Chemistry question 2 of 30.

1 gram of a carbonate (

\mathrm{M_2CO_3}

) on treatment with excess HCl produces 0.01186 mole of

\mathrm{CO_2}

. The molar mass of

\mathrm{M_2CO_3}

in g mol

^{-1}

is :

(1)118.6
(2)11.86
(3)1186
(4)84.3Official answer

Official answer

Option 4

CBSE answer key (25/04/2017, used for result).

Chapter: Some Basic Concepts of Chemistry
Topic: Mole Concept
Idea tested: Molar Mass and Gas Volume

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.