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Saturday, 31 October

JEE Main 2017 · PhysicsMultiple choiceSingle correctMediumData or graph

JEE Main 2 April 2017 (offline), Physics Q12

Question 12 of 90 in this shift, Physics question 12 of 30.

A particle is executing simple harmonic motion with a time period T. At time t=0t=0, it is at its position of equilibrium. The kinetic energy - time graph of the particle will look like :

The figure, in words

Four KE vs t graphs with tick marks on the time axis (T/2, T, T/4 etc.).
  1. (1)[figure: KE vs t graph, two arch-shaped humps starting from 0, with ticks T/2 and T on the axis]
  2. (2)[figure: KE vs t graph, rising curve from 0 (concave) then a cusp touching zero at T and rising again]
  3. (3)[figure: KE vs t graph, cusp-shaped curve touching zero at 0 and at T/2, arches between, tick T]
  4. (4)[figure: KE vs t graph, curve touching zero at T/4 and T/2 (ticks T/4, T/2, T), arches between]Official answer

Official answer

Option 4

CBSE answer key (25/04/2017, used for result).

Chapter
Oscillations
Topic
Energy in SHM
Idea tested
Energy-Time Graphs in SHM

Same idea in other shifts

Asked 2× in all
  1. 27 Aug 2021, Shift 1 · Q9The variation of displacement with time of a particle executing free simple harmonic motion is shown in the figure. The potential energy…MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA (CBSE ran the 2017 exam); answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.